- 1.
- By taking the Fourier Transform of both sides of the
differential equation, and by exploiting the fact that this is a
linear operation and using the Differentiation Theorem of Fourier
analysis, we arrive at the following equation in the frequency domain:
from which it follows that the Fourier Transform of the solution we seek
is simply
Finally, we need to compute the inverse Fourier Transform of
,
and this will give us the solution f(x) that we seek for the
differential equation.
- 2.
- It requires N+1 consecutive sample points in order to
calculate the
derivative of a function in a region.
The weights which need to be multiplied by consecutive samples of the
function in order to calculate its
derivative are: -1,
+3, -3, +1.
- 3.
- The principal advantage is that if orthogonal functions are used, then
the expansion coefficients which give the representation of the function (or
data) in terms of the universal basis functions are obtained merely by
inner product projection. (A normalization factor would also be required if
the basis functions were orthogonal but not orthonormal.) If we used functions
that were non-orthogonal, then a great deal more linear algebra would be required
in order to obtain their desired coefficients.
We must compute the inner product or projection of
and f(x),
which will give us each basis coefficient ak: