BOOL_CASES_TAC : term -> tactic

SYNOPSIS
Performs boolean case analysis on a (free) term in the goal.

DESCRIPTION
When applied to a term x (which must be of type bool but need not be simply a variable), and a goal A ?- t, the tactic BOOL_CASES_TAC generates the two subgoals corresponding to A ?- t but with any free instances of x replaced by F and T respectively.
              A ?- t
   ============================  BOOL_CASES_TAC `x`
    A ?- t[F/x]    A ?- t[T/x]
The term given does not have to be free in the goal, but if it isn't, BOOL_CASES_TAC will merely duplicate the original goal twice. Note that in the new goals, we don't have x and ~x as assumptions; for that use ASM_CASES_TAC.

FAILURE CONDITIONS
Fails unless the term x has type bool.

EXAMPLE
The goal:
  # g `(b ==> ~b) ==> (b ==> a)`;;
can be completely solved by using BOOL_CASES_TAC on the variable b, then simply rewriting the two subgoals using only the inbuilt tautologies, i.e. by applying the following tactic:
  # e(BOOL_CASES_TAC `b:bool` THEN REWRITE_TAC[]);;
  val it : goalstack = No subgoals

USES
Avoiding fiddly logical proofs by brute-force case analysis, possibly only over a key term as in the above example, possibly over all free boolean variables.

SEE ALSO
ASM_CASES_TAC, COND_CASES_TAC, DISJ_CASES_TAC, ITAUT, STRUCT_CASES_TAC, TAUT.